what is the maximum data rate for a 6kHz channel that transmits data using 4 levels (binary) ?(only give the value in bits/second, don't put the unit)

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What is the maximum data rate for a 6kHz channel that transmits data using 4 levels (binary) ?

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Solution

The maximum data rate can be calculated using the Shannon Capacity formula, which is C = B * log2(1 + SNR), where C is the capacity, B is the bandwidth, and SNR is the signal-to-noise ratio. However, in this case, we are not given the SNR, but we are given the number of signal levels (4).

We can use the formula C = B * log2(L), where L is the number of signal levels.

So, C = 6000 * log2(4) = 12000 bits/second.

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what is the maximum data rate for a 6kHz channel that transmits data using 4 levels (binary) ?(only give the value in bits/second, don't put the unit)

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