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A =a1i+a2j+a3k B=b1i +b2j+b3k where |a|=1 and |b|=4 a.b=2 The c=2(a x b) -3b Then find angle between b and c vector

Question

A =a1i+a2j+a3k B=b1i +b2j+b3k where |a|=1 and |b|=4 a.b=2 The c=2(a x b) -3b Then find angle between b and c vector
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Solution 1

To find the angle between vectors b and c, we can use the formula for the dot product of two vectors:

b.c = |b| |c| cos θ

where θ is the angle between the vectors, |b| is the magnitude of vector b, |c| is the magnitude of vector c, and b.c is the dot product of vectors b and c.

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