In which case does the reaction go farthest to completion?Group of answer choicesK = 104K = 103K = 1K = 10-3K = 10-5

1. Break Down the Problem

We need to determine which equilibrium constant $K$ indicates that a chemical reaction goes furthest to completion.

2. Relevant Concepts

The equilibrium constant $K$ gives us insight into the extent of a reaction at equilibrium:

• $K \gg 1$: The reaction favors products, going to completion.
• $K \approx 1$: Significant concentrations of both reactants and products.
• $K \ll 1$: The reaction favors reactants, not proceeding significantly to completion.

3. Analysis and Detail

Let’s analyze the given $K$ values:

1. $K = 10^4$: Very large, indicates that products greatly exceed reactants.
2. $K = 10^3$: Still large, but smaller than $K = 10^4$.
3. $K = 1$: Neither products nor reactants are favored.
4. $K = 10^{-3}$: Favors reactants, not much product formed.
5. $K = 10^{-5}$: Very small, strongly favors reactants.

From the analysis, the larger the value of $K$, the more the reaction is driven to completion.

4. Verify and Summarize

Among the options provided, $K = 10^4$ is the largest, meaning that this case will drive the reaction the farthest toward completion.

Final Answer

The reaction goes farthest to completion in the case of $K = 10^4$.