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Find the slope of a line parallel to the line whose equation is 3, x, plus, 18, y, equals, minus, 4863x+18y=−486. Fully simplify your answer.

Question

Find the slope of a line parallel to the line whose equation is 3x+18y=486 3x + 18y = -486 .

Fully simplify your answer.

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Solution

1. Break Down the Problem

We need to find the slope of a line that is parallel to the given line. The given line is in the standard form Ax+By=CAx + By = C. We need to first convert this equation into slope-intercept form y=mx+by = mx + b, where mm is the slope.

2. Relevant Concepts

For a line in the form Ax+By=CAx + By = C, the slope mm can be found by rearranging it into the form y=mx+by = mx + b.

3. Analysis and Detail

Starting with the equation: 3x+18y=486 3x + 18y = -486

We can isolate yy:

  1. Subtract 3x3x from both sides: 18y=3x486 18y = -3x - 486

  2. Now, divide by 1818 to solve for yy: y=318x48618 y = -\frac{3}{18}x - \frac{486}{18}

  3. Simplify the fractions: y=16x27 y = -\frac{1}{6}x - 27

From this equation, we can see that the slope mm of the line is 16-\frac{1}{6}.

4. Verify and Summarize

Since parallel lines have the same slope, the slope of any line parallel to our given line must also be 16-\frac{1}{6}.

Final Answer

The slope of a line parallel to the given line is 16\mathbf{-\frac{1}{6}}.

This problem has been solved

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