The points at which the tangent passes through the origin for the curve y=4x3−2x5 are
Question
Solution 1
The equation of the tangent line to the curve at a point (x, y) is given by:
y - y1 = m(x - x1)
where (x1, y1) is a point on the curve and m is the slope of the tangent line. The slope of the tangent line is given by the derivative of the function at that point.
The derivative of y = 4x^3 - 2x^5 Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv
Similar Questions
The points at which the tangent passes through the origin for the curve y=4x3−2x5 are
The tangent to the curve C: y=4x^2 at the point A is parallel to the straight line L: 2x-y+24=0. Find the equation of the tangent to C at A.
A curve which passes through (1,2) and whose sub-normal at every point is 2, is
The plane passing through the origin and containing the lines whose direction cosines are proportional to 1,-2,2 and 2,3,-1 passes through the point
Find an equation of the tangent line to the curve y = xx that is parallel to the line y = 6 + 9x.