A metal gas cylinder is heated from 181 K to 296 K.  If the original pressure was 256 psi, what is the pressure after heating also in psi?

To solve this problem, we can use Gay-Lussac's Law which states that the pressure of a gas is directly proportional to its absolute temperature, provided the volume is kept constant. The formula for Gay-Lussac's Law is P1/T1 = P2/T2, where:

• P1 is the initial pressure
• T1 is the initial temperature
• P2 is the final pressure
• T2 is the final temperature

Given in the problem:

• P1 = 256 psi
• T1 = 181 K
• T2 = 296 K
• P2 = ?

We can substitute the given values into the formula and solve for P2:

256 psi / 181 K = P2 / 296 K

Cross-multiplying gives us:

P2 = (256 psi * 296 K) / 181 K

Calculating the above expression will give us the final pressure P2 in psi.