Determine the resulting volume (in cu. units) when enclosed area between the functions below are revolved around the y-axis: 𝑦=𝑥2+1, 𝑦=𝑥2, 𝑦=1 and 𝑦=4

Question

Determine the resulting volume (in cu. units) when enclosed area between the functions below are revolved around the y-axis: 𝑦=𝑥2+1, 𝑦=𝑥2, 𝑦=1 and 𝑦=4
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

To find the volume of the solid formed by revolving the area between the curves around the y-axis, we can use the method of cylindrical shells. The formula for the volume of a cylindrical shell is V = 2π ∫ [r(h) dr] from a to b, where r is the radius and h is the height of the cylindrical shell.

Th Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

Determine the resulting volume (in cu. units) when enclosed area between the functions below are revolved around the y-axis: 𝑦=𝑥2+1, 𝑦=𝑥2, 𝑦=1 and 𝑦=4

The area formed in the first quadrant by  the graphs of 𝑦=𝑥2 and  𝑦=8−𝑥2  is revolved about the y -axis. Using a vertical element, dV is equal to

The area bounded by 𝑥=𝑦2−2 and 𝑥=𝑒𝑦  between  𝑦=−1 and 𝑦=1 is revolved about the line 𝑦=1. The Volume integral for the solid generated is

The volume generated by rotating, about the X𝑋 axis, the region enclosed by y=x32𝑦=𝑥32, x=1,x=2𝑥=1,𝑥=2, and the X𝑋 axis, is Answer 1 Question 9

Find the signed area between the 𝑥-axis and the graph of 𝑦=𝑥2−4 over the interval [2,4]

1/3