Looping-4Read a integer N and print a character pattern with N rows.For example if N=5, the pattern isABBCCCDDDDE E E E E

Sure, here is a Python solution for your problem:

def print_pattern(N):
    for i in range(1, N+1):
        print(str(chr(64 + i)) * i)

print_pattern(5)

This function works by looping from 1 to N (inclusive). For each iteration, it converts the current number to a character (using the ASCII value, where 'A' is 65) and then repeats that character i times.

For example, if N=5, the output will be:

A
BB
CCC
DDDD
EEEEE

This is because in the first iteration, 'A' is printed once. In the second iteration, 'B' is printed twice. In the third iteration, 'C' is printed three times, and so on.