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The output of the code will be ____. int i=5; printf(“%d %d %d”, i, i++, ++i); ans. 7 6 5 7 6 6 5 5 7 7 6 7

Question

The output of the code will be ____.

int i=5;
printf("%d %d %d", i, i++, ++i);

ans.

  1. 7 6 5
  2. 7 6 6
  3. 5 5 7
  4. 7 6 7
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Solution

To determine the output of the provided code snippet, we need to analyze the behavior of the printf function in C regarding the order of evaluation of its arguments.

1. Break Down the Problem

  • We have an integer variable i initialized to 5.
  • We need to evaluate the statement printf("%d %d %d", i, i++, ++i);.

2. Relevant Concepts

  • In C, the order of evaluation of function arguments is unspecified which means that the compiler may evaluate them in any order.
  • The i++ is a post-increment, which will return the current value before incrementing. Thus, it returns 5 and increases i to 6 after this expression is evaluated.
  • The ++i is a pre-increment, which increases the value of i by 1 before returning. At this point, since i was 6 after the post-increment, ++i will return 7.

3. Analysis and Detail

  1. Initially, i is 5.
  2. When printf is called:
    • Assuming i is evaluated first, it outputs 5.
    • Next, the expression i++ is evaluated, which gives 5 (since it returns the current value of i and then increments it to 6).
    • Finally, ++i is evaluated, yielding 7 (it first increments i to 7 and then returns this value).

Due to the unspecified order, one can encounter different behavior based on how the compiler handles the evaluation of arguments, but here is a plausible evaluation order:

  • The evaluations may give i, i++, and then ++i, which results in:
    • i = 7 (after ++i is executed last).
    • i++ returns the original i before increment: 5.
    • ++i returns 7 after i was incremented to 7.

4. Verify and Summarize

  • However, depending on the compiler's evaluation order, we have to consider different outputs.
    • If printf evaluates in some other order, it can potentially yield different outputs based on the modification of i during evaluation.

Final Answer

The most plausible output given the explanation would be 7 6 7, but it's essential to note that the behavior can vary depending on compiler optimizations and specifics of argument evaluation order. The correct answer from the choices provided is indeed 7 6 7.

This problem has been solved

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