In aqueous solution of Al2(SO4)3 concentration of Al+3 is 1.8 M then what is the concentration ofSO4–2

The formula for aluminum sulfate is Al2(SO4)3. This tells us that for every 1 formula unit of Al2(SO4)3 that dissolves, we get 2 Al+3 ions and 3 SO4-2 ions.

Given that the concentration of Al+3 is 1.8 M, we can use the stoichiometry of the reaction to find the concentration of SO4-2.

Since there are 3 moles of SO4-2 for every 2 moles of Al+3, we can set up the following ratio:

(3 moles SO4-2 / 2 moles Al+3) = x moles SO4-2 / 1.8 moles Al+3

Solving for x gives us the concentration of SO4-2:

x = (3/2) * 1.8 = 2.7 M

So, the concentration of SO4-2 is 2.7 M.