A solution of Cs2SO4 at 2.0 M is diluted from its original volume of 0.6 L by adding 0.4 L. What is the resulting concentration of this solution?

Question

A solution of Cs2SO4 at 2.0 M is diluted from its original volume of 0.6 L by adding 0.4 L. What is the resulting concentration of this solution?
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The concentration of a solution after dilution can be calculated using the formula M1V1 = M2V2, where M1 and V1 are the initial molarity and volume, and M2 and V2 are the final molarity and volume.

Here, M1 = 2.0 M, V1 = 0.6 L, and V2 = V1 + volume of solvent added = 0.6 L + 0.4 L = 1.0 L.

We can Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

A solution of Cs2SO4 at 2.0 M is diluted from its original volume of 0.6 L by adding 0.4 L. What is the resulting concentration of this solution?

A solution of LiNO3 at 2 M is diluted from a volume of 1 L to its new volume of 1.78 L. What is the resulting concentration of this solution?

Calculate the volume of solution that can be prepared when 300.0 mg of citric acid is diluted to a concentration of 0.500 g dm–3 solution.

A solution contains 2.5 cm3 of alcohol mixed with 75 cm3 of water. Calculate the concentration of this solution by volume

Enough water is added to 50.0 mL of a 0.660 M NaOH solution in order to bring the total volume to 450.0 mL. What is the molarity of this diluted solution?

1/3