To solve this problem, we can use the concept of permutations and combinations.

Step 1: Arrange the 7 boys around the round table. The number of ways to do this is (7-1)! = 6! because in a circular arrangement, we consider one point as a reference and arrange the others in relation to that point.

Step 2: Now, we have 8 spaces (between the boys and at the ends) where we can place the 5 girls such that no two girls are sitting together. The number of ways to do this is 8P5 = 8!/(8-5)! = 6720.

Step 3: Multiply the results from step 1 and step 2 to get the total number of arrangements. So, 6! * 6720 = 2,903,040.

So, there are 2,903,040 ways in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together.

Question

To solve this problem, we can use the concept of permutations and combinations.

Step 1: Arrange the 7 boys around the round table. The number of ways to do this is (7-1)! = 6! because in a circular arrangement, we consider one point as a reference and arrange the others in relation to that point.

Step 2: Now, we have 8 spaces (between the boys and at the ends) where we can place the 5 girls such that no two girls are sitting together. The number of ways to do this is 8P5 = 8!/(8-5)! = 6720.

Step 3: Multiply the results from step 1 and step 2 to get the total number of arrangements. So, 6! * 6720 = 2,903,040.

So, there are 2,903,040 ways in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together.

Knowee AI · Accepted Answer

To solve this problem, we can use the concept of permutations and combinations.

Step 1: Arrange the 7 boys around the round table. The number of ways to do this is (7-1)! = 6! because in a circular arrangement, we consider one point as a reference and arrange the others in relation to that point.

Step 2: Now, we have 8 spaces (between the boys and at the ends) where we can place the 5 girls such that no two girls are sitting together. The number of ways to do this is 8P5 = 8!/(8-5)! = 6720.

Step 3: Multiply the results from step 1 and step 2 to get the total number of arrangements. So, 6! * 6720 = 2,903,040.

So, there are 2,903,040 ways in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together.

The number of ways, in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together is

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The number of ways, in which 5 girls and 7 boys can be seated at a round table so that no two girls sit together is

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