What least number must be added to 2010 to obtain a number which is completely divisible by 19?Options :A.5B.4C.3D.None of these
Question
What least number must be added to 2010 to obtain a number which is completely divisible by 19?
Options:
A. 5
B. 4
C. 3
D. None of these
Solution
To solve this problem, we need to find the remainder when 2010 is divided by 19.
Step 1: Divide 2010 by 19.
2010 ÷ 19 = 105 remainder 15
This means that 2010 is 15 more than a multiple of 19.
Step 2: Subtract the remainder from 19.
19 - 15 = 4
So, the least number that must be added to 2010 to obtain a number which is completely divisible by 19 is 4.
Therefore, the answer is B. 4.
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