A spring with a spring constant of 4 N/m is stretched by 0.5 m.How much elastic potential energy did it gain?
Question
Solution 1
The elastic potential energy (U) stored in a stretched or compressed spring is given by the formula:
U = 0.5 * k * x^2
where:
- k is the spring constant, and
- x is the amount the spring is stretched or compressed from its equilibrium position.
In this case, the spring constant k is 4 N/m and the Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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