Use the stoichiometry of reaction in Reaction RY.2 to calculate moles of CaCl2 needed to produce 2.00 g ofCaCO3.

Sure, here are the steps to calculate the moles of CaCl2 needed to produce 2.00 g of CaCO3 using stoichiometry:

1. Write down the balanced chemical equation for the reaction. For this example, let's assume the reaction is: CaCl2 + Na2CO3 -> CaCO3 + 2NaCl (Reaction RY.2)

2. Calculate the molar mass of CaCO3. The molar mass of CaCO3 is approximately 100.09 g/mol.

3. Convert the given mass of CaCO3 to moles. To do this, divide the given mass by the molar mass. So, 2.00 g CaCO3 * (1 mol CaCO3 / 100.09 g CaCO3) = 0.02 mol CaCO3.

4. Use the stoichiometry of the reaction to find the moles of CaCl2. From the balanced chemical equation, we can see that 1 mole of CaCl2 produces 1 mole of CaCO3. Therefore, the moles of CaCl2 needed are equal to the moles of CaCO3, which is 0.02 mol.

So, you would need 0.02 moles of CaCl2 to produce 2.00 g of CaCO3.