How many grams of Ca2+ in 42.51 g of limestone (CaCO3)? Answer to 2 decimal pointsMW (Ca) = 40.08 g.mol-1MW (CaCO3) = 100.09 g.mol-1
Question
Solution 1
Step 1: Identify the given values
The mass (m) of CaCO3 = 42.51 g The molar mass (M) of CaCO3 = 100.09 g/mol The molar mass (M) of Ca = 40.08 g/mol
Step 2: Calculate the number of moles (n) of CaCO3
The formula to calculate the number of moles is:
n = m/M
Substitute the given values into the fo Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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