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A and B are two numbers such that A>B>838. The difference between the cubes of A and B is D. Then (D-1) can be divisible by ?

Question

A and B are two numbers such that A > B > 838. The difference between the cubes of A and B is D. Then (D - 1) can be divisible by ?

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Solution

Let's break down the problem step by step:

  1. We are given that A and B are two numbers such that A > B > 838.
  2. We need to find the difference between the cubes of A and B, which we'll call D.
  3. The formula for finding the difference between the cubes of two numbers is (A^3 - B^3).
  4. To simplify the expression, we can use the identity (A^3 - B^3) = (A - B)(A^2 + AB + B^2).
  5. Since A > B, we know that (A - B) is a positive number.
  6. Now, let's focus on the expression (A^2 + AB + B^2).
  7. We can rewrite this expression as (A^2 + 2AB + B^2 - AB).
  8. Simplifying further, we get (A + B)^2 - AB.
  9. Since A > B, we know that (A + B) is greater than 2B.
  10. Therefore, (A + B)^2 - AB is greater than 4B^2 - AB.
  11. Since A > 838, we can assume that A is a large number.
  12. As a result, (A + B)^2 - AB is a large number as well.
  13. Now, let's consider the expression (D - 1).
  14. Since D is the difference between the cubes of A and B, we know that D is a positive number.
  15. Therefore, (D - 1) is also a positive number.
  16. To determine if (D - 1) is divisible by a certain number, we need to know the value of D.
  17. Without knowing the specific values of A and B, we cannot determine the exact value of D.
  18. However, based on the previous steps, we can conclude that (D - 1) is likely to be a large positive number.
  19. Therefore, (D - 1) can be divisible by various numbers, depending on the specific value of D.

In conclusion, without knowing the specific values of A and B, we cannot determine the exact number by which (D - 1) is divisible. However, based on the given information, we can infer that (D - 1) is likely to be a large positive number and can be divisible by multiple numbers.

This problem has been solved

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