The pseudocode provided is a recursive function that prints the value of `k` and calls itself with `k+2` until `k` is greater than 155. Here's how it would execute for `k=150`:

1. Call `fun(150)`. Since `150` is not greater than `155`, it will print `150` and call `fun(152)`.
2. Call `fun(152)`. Since `152` is not greater than `155`, it will print `152` and call `fun(154)`.
3. Call `fun(154)`. Since `154` is not greater than `155`, it will print `154` and call `fun(156)`.
4. Call `fun(156)`. Since `156` is greater than `155`, it will return and not print anything.
5. After each function call returns, it will print `k` again. So it will print `154`, `152`, and `150` in that order.

So, the output of the pseudocode for `k=150` will be `150, 152, 154, 154, 152, 150`.

Question

The pseudocode provided is a recursive function that prints the value of `k` and calls itself with `k+2` until `k` is greater than 155. Here's how it would execute for `k=150`:

1. Call `fun(150)`. Since `150` is not greater than `155`, it will print `150` and call `fun(152)`.
2. Call `fun(152)`. Since `152` is not greater than `155`, it will print `152` and call `fun(154)`.
3. Call `fun(154)`. Since `154` is not greater than `155`, it will print `154` and call `fun(156)`.
4. Call `fun(156)`. Since `156` is greater than `155`, it will return and not print anything.
5. After each function call returns, it will print `k` again. So it will print `154`, `152`, and `150` in that order.

So, the output of the pseudocode for `k=150` will be `150, 152, 154, 154, 152, 150`.

Knowee AI · Accepted Answer

The pseudocode provided is a recursive function that prints the value of `k` and calls itself with `k+2` until `k` is greater than 155. Here's how it would execute for `k=150`:

1. Call `fun(150)`. Since `150` is not greater than `155`, it will print `150` and call `fun(152)`.
2. Call `fun(152)`. Since `152` is not greater than `155`, it will print `152` and call `fun(154)`.
3. Call `fun(154)`. Since `154` is not greater than `155`, it will print `154` and call `fun(156)`.
4. Call `fun(156)`. Since `156` is greater than `155`, it will return and not print anything.
5. After each function call returns, it will print `k` again. So it will print `154`, `152`, and `150` in that order.

So, the output of the pseudocode for `k=150` will be `150, 152, 154, 154, 152, 150`.

What will be the value of the following pseudocode for k=150?fun(integer k)if(k>155)returnend ifprint kfun(k+2)print kEnd of function fun()

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What will be the value of the following pseudocode for k=150?

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