What will be the value of the following pseudocode?Integer x, yfor(each x from 1 to 11)x = x + 2end forPrint xQuestion 84AnswerA.10B.12C.13D.11

The pseudocode provided is a loop that iterates from 1 to 11, and for each iteration, it adds 2 to the current value of x. However, the loop does not specify what happens to y, so we can ignore it for now.

Let's break it down:

1. Initialize x to 1 (the start of the loop).
2. Add 2 to x, making x equal to 3.
3. Repeat steps 1 and 2 for each value from 1 to 11.

However, there seems to be a mistake in the pseudocode. The variable x is both the loop variable and the variable being modified within the loop. This would typically result in an error in most programming languages.

Assuming that the loop variable and the variable being modified are intended to be separate, the pseudocode would look something like this:

Integer x, i
x = 0
for(each i from 1 to 11)
    x = x + 2
end for
Print x

In this case, the loop runs 11 times, and each time it adds 2 to x. So, the final value of x would be 11 * 2 = 22.

However, none of the provided options (A.10, B.12, C.13, D.11) match this result. This suggests that there may be a mistake in the question or the provided options.