Simplify $6\sqrt[3]{128t}-2\sqrt[3]{2t}$63√128t−23√2t .The simplified expression is .

Question

The simplified expression is .

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The expression you provided is: $6\sqrt[3]{128t}-2\sqrt[3]{2t}$

First, we can simplify the cube roots. The cube root of 128 is 4√2 and the cube root of 2 is √2. So, the expression becomes:

$6\sqrt[3]{4^3*2t}-2\sqrt[3]{2t}$

This simplifies to:

$6*4\sqrt[3]{2t}-2\sqrt[3]{2t}$

Which simplifies to:

$24\sqrt[3]{2t}-2\sqrt[3]{2t}$

Finally, we can combine like terms to get:

$22\sqrt[3]{2t}$

So, the simplified expression is $22\sqrt[3]{2t}$ .

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