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For 16 bit compiler, allowable range for integer constants is ______ ?Options-3.4e38 to 3.4e38-32767 to 32768-32768 to 32767-32668 to 32667

Question

For 16 bit compiler, allowable range for integer constants is ______ ?

Options:

  • 3.4e38 to 3.4e38
  • -32767 to 32768
  • -32768 to 32767
  • -32668 to 32667
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Solution

To determine the allowable range for integer constants in a 16-bit compiler, we need to consider how integers are represented in a 16-bit system.

1. Break Down the Problem

  • A 16-bit integer can represent values using bits.
  • We need to consider the two types of integer representations: signed and unsigned.

2. Relevant Concepts

  • In a signed 16-bit integer (using two's complement representation), the range is calculated as: 2(n1) to 2(n1)1 -2^{(n-1)} \text{ to } 2^{(n-1)} - 1 where n n is the number of bits.

  • For 16 bits, the range is: 215 to 2151(sincen=16) -2^{15} \text{ to } 2^{15} - 1 \quad (since \, n = 16) Therefore: 32768 to 32767 -32768 \text{ to } 32767

3. Analysis and Detail

  • The lower limit is 32768 -32768 (which is 215-2^{15}).
  • The upper limit is 32767 32767 (which is 21512^{15} - 1).

4. Verify and Summarize

The calculations confirm that the signed 16-bit integer representation provides a range from 32768 -32768 to 32767 32767 .

Final Answer

The allowable range for integer constants in a 16-bit compiler is -32768 to 32767.

This problem has been solved

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