In a chi-square contingency table test for independence, there are six rows and five columns. The computed chi-square value is 46. The p-value is:

To determine the p-value in a chi-square test for independence, you need to know the degrees of freedom and the chi-square statistic.

The degrees of freedom for a chi-square test for independence is calculated as (number of rows - 1) * (number of columns - 1). In this case, with six rows and five columns, the degrees of freedom would be (6-1)*(5-1) = 20.

The chi-square statistic is given as 46.

With these values, you would then look up the p-value associated with a chi-square of 46 and 20 degrees of freedom in a chi-square distribution table, or use a statistical software or online calculator to find the p-value.

However, without a chi-square distribution table or a calculator at hand, I can't provide the exact p-value. But given the high chi-square value, it's likely that the p-value is quite small, indicating a significant result.