What is the output of the following function calldef fun1(name, age=20): print(name, age) fun1('Emma', 25)Emma 25Emma 20Emma 22
Question
What is the output of the following function call?
def fun1(name, age=20):
print(name, age)
fun1('Emma', 25)
- Emma 25
- Emma 20
- Emma 22
Solution
The output of the function call fun1('Emma', 25) will be Emma 25.
Here's the step by step explanation:
-
The function
fun1is defined with two parameters:nameandage. Theageparameter has a default value of 20. -
When you call the function with the arguments 'Emma' and 25 (
fun1('Emma', 25)), 'Emma' is passed as thenameand 25 is passed as theage. -
Inside the function, these values are printed. So,
Emma 25is printed.
The other outputs Emma 20 and Emma 22 are not produced by this function call. They might be the result of other calls to the function fun1 with different arguments.
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