48 liters of a mixture has 75% alcohol. How much water must be added to it to get 60% alcohol concentration ? (in liters)Options :1215168

To solve this problem, we first need to determine the amount of alcohol in the original mixture.

1. Calculate the amount of alcohol in the original mixture: 48 liters * 75% = 36 liters of alcohol

2. Then, we need to find out how much total mixture we would need if we want the alcohol to be 60% of the total mixture. We can set up the following equation to solve for this: 36 liters (amount of alcohol) = 60% * total mixture

3. Solve the equation for the total mixture: total mixture = 36 liters / 60% = 60 liters

4. Finally, subtract the original amount of mixture from the total amount of mixture needed to find out how much water needs to be added: 60 liters - 48 liters = 12 liters

So, 12 liters of water must be added to the mixture to get a 60% alcohol concentration. The correct option is 1.