Given the set, A = {-4, -2, 0, 2, 4, 6}, what are the members of x in the proposition,(∃𝑥 ∈ 𝐴)(𝑥 + 2 ≤ 5)
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Solution 1
The proposition (∃𝑥 ∈ 𝐴)(𝑥 + 2 ≤ 5) translates to "There exists an x in set A such that x + 2 is less than or equal to 5".
To find the members of x that satisfy this condition, we need to subtract 2 from both sides of the inequality, which gives us x ≤ 3.
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