Prove that if G is an undirected bipartite graph with an odd number of vertices,then G is nonhamiltonian.

Question

Prove that if G is an undirected bipartite graph with an odd number of vertices,then G is nonhamiltonian.
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Solution 1

To prove that if ( G ) is an undirected bipartite graph with an odd number of vertices, then ( G ) is nonhamiltonian, we can proceed as follows:

  1. Definition of Bipartite Graph: Recall that a bipartite graph ( G ) can be divided into two disjoint sets of vertices, say ( U ) and ( V ) Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
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