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18. int value = 453;19. int d1 = value % 10;20. int d2 = (value / 10) % 10;21. int d3 = (value / 100) % 10;22. System.out.println("" + d1 + d2 + d3);23. }24. }

Question

Code Snippet

int value = 453;
int d1 = value % 10;
int d2 = (value / 10) % 10;
int d3 = (value / 100) % 10;
System.out.println("" + d1 + d2 + d3);
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Solution

This is a piece of Java code. Here's a step-by-step explanation of what it does:

  1. int value = 453; This line declares an integer variable named value and assigns it the value of 453.

  2. int d1 = value % 10; This line declares an integer variable named d1 and assigns it the value of the remainder when value is divided by 10. In this case, value is 453, so d1 is 3 (the last digit of 453).

  3. int d2 = (value / 10) % 10; This line declares an integer variable named d2 and assigns it the value of the remainder when value divided by 10 is further divided by 10. In this case, value is 453, so value / 10 is 45 (integer division discards the remainder), and 45 % 10 is 5 (the second last digit of 453).

  4. int d3 = (value / 100) % 10; This line declares an integer variable named d3 and assigns it the value of the remainder when value divided by 100 is further divided by 10. In this case, value is 453, so value / 100 is 4 (integer division discards the remainder), and 4 % 10 is 4 (the first digit of 453).

  5. System.out.println("" + d1 + d2 + d3); This line prints the values of d1, d2, and d3 concatenated together as a string. In this case, it will print "354".

  6. } and } These are closing braces, likely for a method and a class, but without the rest of the code, it's hard to say for sure.

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