The radius of the innermost electron orbit of a hydrogen atom is5.3×10–11 m. The radius of the n =3 orbit is

The radius of an electron orbit in a hydrogen atom is given by the formula:

r = n² * r₀

where:

• r is the radius of the orbit,
• n is the principal quantum number (the number of the orbit, starting from 1),
• r₀ is the radius of the innermost orbit (the first orbit, also known as the Bohr radius).

In this case, you are given that r₀ = 5.3×10⁻¹¹ m and you are asked to find the radius of the n = 3 orbit.

Substitute the given values into the formula:

r = 3² * 5.3×10⁻¹¹ m r = 9 * 5.3×10⁻¹¹ m r = 47.7×10⁻¹¹ m

So, the radius of the n = 3 orbit is 47.7×10⁻¹¹ m.