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The radius of the second Bohr orbit of Li+2 ion, in terms of the Bohr radius (a0) of hydrogen atom is

Question

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Solution

The Bohr model of an atom states that the radius of an electron's orbit around the nucleus of an atom is directly proportional to the square of the electron's energy level (n^2) and inversely proportional to the atomic number (Z).

The Li+2 ion has an atomic number of 3 (Z=3) and we are looking for the radius of the second Bohr orbit, so the energy level is 2 (n=2).

The formula for the radius of a Bohr orbit is:

r = n^2/Z * a0

Substituting the given values:

r = (2^2/3) * a0 = 4/3 * a0

So, the radius of the second Bohr orbit of Li+2 ion, in terms of the Bohr radius (a0) of hydrogen atom is 4/3 a0.

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