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Draw all the monobromo derivatives of the following alkane, ignoring stereochemistry.

Question

Draw all the monobromo derivatives of the following alkane, ignoring stereochemistry.

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Solution

To draw all the monobromo derivatives of an alkane, you need to consider the structure of the starting alkane and the positions where bromine can be substituted. Let's choose an example alkane - hexane (C6H14)(\text{C}_6\text{H}_{14}).

1. Identify the Alkane

Hexane has the structural formula: C6H14(Straight-chain) \text{C}_6\text{H}_{14} \quad \text{(Straight-chain)} The structure can be represented as:

   H   H   H   H   H   H
   |   |   |   |   |   |
H--C---C---C---C---C---C--H
   |   |   |   |   |   |
   H   H   H   H   H   H

2. Identify Possible Substitution Sites

Since hexane is a straight-chain alkane, bromine can be substituted at any of the six carbon atoms leading to:

  • C-1
  • C-2
  • C-3
  • C-4
  • C-5
  • C-6

3. Draw Monobromo Derivatives

For each carbon, substitute one hydrogen with a bromine atom (Br) (\text{Br}) . Below are the monobromo derivatives:

  1. 1-bromohexane:
    Br
    |
    H   H   H   H   H
    |   |   |   |   |
    

H--C---C---C---C---C--C--H | | | | | | H H H H H H


2. **2-bromohexane**:
   Br
   |

H H H H | | | | H--C---C---C---C---C--H | | | | | | H H H H H


3. **3-bromohexane**:
       Br
       |

H H H | | | H--C---C---C---H | | | | H H H H


4. **4-bromohexane**:
           Br
           |

H H H H | | | | H--C---C---C---C---H | | | | H H H H


5. **5-bromohexane**:
               Br
               |

H H H H | | | | H--C---C---C---C---C--H | | | | | H H H H H


6. **6-bromohexane**:
                   Br
                   |

H H H H H | | | | | H--C---C---C---C---C---H | | | | | H H H H H


### Final Note
Since the question specifies to ignore stereochemistry, there is no need to represent any stereoisomers, and we focus solely on the position of the bromine substitution within the molecular structure.

### Summary of Monobromo Derivatives
The total derivatives can be summarized as:
- 1-bromohexane
- 2-bromohexane
- 3-bromohexane
- 4-bromohexane
- 5-bromohexane
- 6-bromohexane 

Each derivative reflects a different position of bromine substitution on the hexane molecule.

This problem has been solved

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