An isomer of C6H14 forms three monochloro derivatives. The isomer may be -(Excluding stereo isomer)neo-pentanen-hexane2, 3-dimethylbutaneiso-hexane
Question
An isomer of C6H14 forms three monochloro derivatives.
The isomer may be:
- neo-pentane
- hexane
- 2, 3-dimethylbutane
- iso-hexane
Solution
The isomer of C6H14 that forms three monochloro derivatives is 2,3-dimethylbutane.
Here's why:
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Draw the structure of 2,3-dimethylbutane. It has a four-carbon chain with two methyl groups attached to the second and third carbons.
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Identify the hydrogens that could be replaced by chlorine to form a monochloro derivative. There are three types of hydrogens: those on the end carbons of the main chain, those on the second and third carbons of the main chain, and those on the methyl groups.
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Each of these types of hydrogens will give a different monochloro derivative when replaced by chlorine. Therefore, 2,3-dimethylbutane can form three monochloro derivatives.
The other isomers of C6H14 (n-hexane, iso-hexane, and neo-pentane) can form more than three monochloro derivatives, so they are not the correct answer.
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