Find the volume of the region below the graph of f (x, y) = 16 − x2 − y2 and above thexy-plane in the first octant. Hint: convert to polar coordinates
Question
Solution 1
To find the volume of the region below the graph of f(x, y) = 16 - x² - y² and above the xy-plane in the first octant, we can use a triple integral in polar coordinates. Here are the steps:
Convert the function to polar coordinates: f(r, θ) = 16 - r², where r² = x² + y².
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