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If n is an integer such that 1nn352 is a six-digit number exactly divisible by 24, what will be the sum of the possible values of n?

Question

If n is an integer such that 1nn352 is a six-digit number exactly divisible by 24, what will be the sum of the possible values of n?

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Solution

To find the possible values of n, we need to understand the rules of divisibility by 24. A number is divisible by 24 if it is divisible by both 3 and 8.

  1. Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3. In this case, the sum of the digits is 1 + n + n + 3 + 5 + 2 = 11 + 2n. For this to be divisible by 3, 2n must be 1 or 4 or 7. So, the possible values of n are 0.5, 2, 3.5. But n is an integer, so n can only be 2.

  2. Divisibility by 8: A number is divisible by 8 if the number formed by the last three digits is divisible by 8. In this case, the last three digits form the number 35n. For this to be divisible by 8, n must be 2 or 6.

Therefore, the only possible value of n that satisfies both conditions is 2. So, the sum of the possible values of n is 2.

This problem has been solved

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