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Find the open intervals on which the function ๐‘“ is increasing or decreasing, and find the ๐‘ฅ-values of all relative extrema (turning points).๐‘“(๐‘ฅ)=18โ‹…๐‘ฅโˆ’๐‘ฅ3

Question

Find the open intervals on which the function f f is increasing or decreasing, and find the x x -values of all relative extrema (turning points).

Given the function:
f(x)=18โ‹…xโˆ’x3 f(x) = 18 \cdot x - x^3

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Solution

To find the open intervals on which the function ๐‘“ is increasing or decreasing, and the ๐‘ฅ-values of all relative extrema (turning points), we need to follow these steps:

Step 1: Find the derivative of the function The derivative of the function ๐‘“(๐‘ฅ)=18โ‹…๐‘ฅโˆ’๐‘ฅยณ is ๐‘“'(๐‘ฅ)=18-3๐‘ฅยฒ.

Step 2: Set the derivative equal to zero and solve for x Setting the derivative equal to zero gives us 18-3๐‘ฅยฒ=0. Solving for x gives us x=ยฑโˆš6.

Step 3: Determine the intervals of increase and decrease We can use a number line to determine where the function is increasing and decreasing. We test the intervals (-โˆž, -โˆš6), (-โˆš6, โˆš6), and (โˆš6, โˆž) by choosing test points in these intervals and substituting them into the derivative.

For the interval (-โˆž, -โˆš6), we can choose x=-โˆš7. Substituting this into the derivative gives us a positive value, so the function is increasing on this interval.

For the interval (-โˆš6, โˆš6), we can choose x=0. Substituting this into the derivative gives us a positive value, so the function is increasing on this interval.

For the interval (โˆš6, โˆž), we can choose x=โˆš7. Substituting this into the derivative gives us a negative value, so the function is decreasing on this interval.

Step 4: Find the x-values of all relative extrema The x-values of all relative extrema are the values of x where the function changes from increasing to decreasing or vice versa. From our number line, we can see that the function changes from increasing to decreasing at x=โˆš6, so this is a relative maximum. The function does not change from decreasing to increasing, so there are no relative minima.

So, the function is increasing on the intervals (-โˆž, -โˆš6) and (-โˆš6, โˆš6), and decreasing on the interval (โˆš6, โˆž). The x-value of the relative maximum is โˆš6.

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