A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the distance travelled in m.
Question
Solution 1
To find the distance traveled by the body, we need to consider the two parts of its motion separately: the upward motion and the downward motion.
- Upward motion: The body rises vertically upward to a height of 100 m in 5 seconds. We can use the equation of motion for uniformly accelerated motion: Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI
Similar Questions
A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the displacement of the body.
A body is thrown vertically upward with 45 m/s. Distance travelled by the body in 5th second is (g = 10 m/s2)
How high would a ball go if it is thrown vertically upward and returns to launching position after 8 seconds?*1 pointA. 7.84 mB. 31.36 mC..78.4 mD. 313.6 m
A ball is thrown vertically upwards with a velocity of 49 m/s and g =9.8 m/s2Calculate the max height it rises up to?112.5 m
A PARTICLE IS MOVING ALONG A STRAIGHT LINE. ITS POSITION X AT TIME T IS GIVEN BY X=2T^3-3T^+2 FIND THE DISTANCE TRAVELLED BY THE PARTICLE IN THE FIRST 5 SECONDS
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.