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What will be the output of the following Pseudocode? int a=9, b=7, c=8, d=4, e e = (a + b + c + d) / 4 if (e >5) print "PASS" else print "FAIL"FAIL01PASS

Question

What will be the output of the following Pseudocode?

int a=9, b=7, c=8, d=4, e  
e = (a + b + c + d) / 4  
if (e > 5)  
    print "PASS"  
else  
    print "FAIL"

FAIL
01
PASS

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Solution

The pseudocode provided calculates the average of four numbers (a, b, c, d) and assigns it to the variable e. Then it checks if e is greater than 5. If it is, it prints "PASS". Otherwise, it prints "FAIL".

Let's break it down:

  1. Initialize the variables: a=9, b=7, c=8, d=4.
  2. Calculate the average of these four numbers: e = (a + b + c + d) / 4. This results in e = (9 + 7 + 8 + 4) / 4 = 28 / 4 = 7.
  3. Check if e is greater than 5: 7 > 5 is true.
  4. Since the condition is true, print "PASS".

So, the output of the pseudocode will be "PASS".

This problem has been solved

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