The ionization energy of a hypothetical atom is 50 eV . If this atom obeys Bohr’s atomic model,the energy of electron in its fifth orbit will be?

Sure, let's solve this step by step.

1. First, we need to understand that the ionization energy is the energy required to remove an electron from the ground state (n=1) of an atom. In this case, the ionization energy is given as 50 eV.

2. According to Bohr's model, the energy of an electron in the nth orbit of an atom is given by the formula: E = -13.6/n^2 eV, where n is the number of the orbit.

3. We know that the energy of the electron in the ground state (n=1) is equal to the ionization energy, so we can set up the equation: -13.6/1^2 = -50 eV.

4. Solving this equation, we find that the energy of the electron in the ground state is -50 eV.

5. Now, we want to find the energy of the electron in the fifth orbit (n=5). We can use the same formula: E = -13.6/n^2 eV.

6. Substituting n=5 into the equation, we get: E = -13.6/5^2 eV = -13.6/25 eV = -0.544 eV.

So, the energy of the electron in its fifth orbit is -0.544 eV.