The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is ___________.Choices:- 20 30 40 50
Question
The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is ___________.
Choices:-
- 20
- 30
- 40
- 50
Solution
Let's denote the three numbers as a, b, and c.
From the problem, we have two equations:
- a² + b² + c² = 138
- ab + bc + ac = 131
We need to find the sum of the numbers, which is a + b + c.
We know that (a + b + c)² = a² + b² + c² + 2(ab + bc + ac).
Substituting the given values into this equation, we get:
(a + b + c)² = 138 + 2*131 = 400
Taking the square root of both sides, we find that a + b + c = 20.
So, the sum of the three numbers is 20.
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