A projectile is fired with an initial speed of 68 m/s at an angle of 55° above the horizontal plane. Determine the maximum height reached by the projectile.
Question
Solution 1
To solve this problem, we will use the formula for the maximum height reached by a projectile, which is given by:
h = (v^2 * sin^2(θ)) / (2 * g)
where:
- v is the initial speed of the projectile,
- θ is the angle at which the projectile is launched,
- g is the acceleration due to gravity.
Given:
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