A 10 mL10 mL hydrocarbon (CxHy)CxHy on combustion gives 40 mL40 mL CO2CO2 and 50 mL H2O50 mL H2O. Calculate the value of x+y.

The combustion reaction of a hydrocarbon can be represented as follows:

CxHy + O2 -> xCO2 + y/2H2O

From the problem, we know that 10 mL of hydrocarbon produces 40 mL of CO2 and 50 mL of H2O.

The volume ratio of CO2 to the hydrocarbon is 40 mL / 10 mL = 4. This means that the number of moles of CO2 is four times the number of moles of the hydrocarbon. Since each mole of hydrocarbon produces x moles of CO2, we can conclude that x = 4.

Similarly, the volume ratio of H2O to the hydrocarbon is 50 mL / 10 mL = 5. This means that the number of moles of H2O is five times the number of moles of the hydrocarbon. Since each mole of hydrocarbon produces y/2 moles of H2O, we can conclude that y/2 = 5, or y = 10.

Therefore, the values of x and y are 4 and 10, respectively. The sum of x and y is 4 + 10 = 14.