Findthe7thtermofthesequencedescribedbelow,wherenrepresentsthepositionofaterminthesequence.an =  13(2)n − 1Write your answer as a decimal or integer.a7 = Submit

1. Break Down the Problem

We need to find the 7th term of the sequence given by the formula $a_n = 13(2)^{n-1}$. This can be done by substituting $n = 7$ into the sequence formula.

2. Relevant Concepts

The formula for the sequence is $a_n = 13(2)^{n-1}$. We will replace $n$ with 7 to solve for $a_7$.

3. Analysis and Detail

Substituting $n = 7$: $a_7 = 13(2)^{7-1}$ Calculating the exponent: $7 - 1 = 6$ So we have: $a_7 = 13(2^6)$ Calculating $2^6$: $2^6 = 64$ Now substituting back: $a_7 = 13 \cdot 64$

4. Verify and Summarize

Now we calculate: $13 \cdot 64 = 832$

Final Answer

The 7th term of the sequence is $a_7 = 832$.