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The graph of 𝑦=𝐴sin⁡𝐵𝑥 has amplitude =|𝐴| and period =2𝜋𝐵.Group of answer choicesTrueFalse

Question

The graph of y = A sin(Bx) has amplitude = |A| and period = 2π/B.

Group of answer choices

  • True
  • False
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Solution

1. Break Down the Problem

We need to determine if the statement about the graph y=Asin(Bx) y = A \sin(Bx) regarding amplitude and period is true or false.

2. Relevant Concepts

  • The amplitude of the sine function represented by y=Asin(Bx) y = A \sin(Bx) is defined as A |A| .
  • The period of the sine function is calculated using the formula Period=2πB \text{Period} = \frac{2\pi}{|B|} .

3. Analysis and Detail

  • Amplitude: The amplitude is indeed given by A |A| .
  • Period: The period specified in the statement is 2πB 2\pi B . However, the correct formula is 2πB \frac{2\pi}{|B|} .

4. Verify and Summarize

Since the period stated in the problem is incorrect, we can conclude that the statement as a whole is false.

Final Answer

False

This problem has been solved

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