The Responsivity of photodiode is 0.294 A/W at wavelength of 0.90 μm. Determine quantum efficiency.a.0.249b.0.654c.0.405d.0.914
Question
The Responsivity of photodiode is 0.294 A/W at wavelength of 0.90 μm. Determine quantum efficiency.
a. 0.249
b. 0.654
c. 0.405
d. 0.914
Solution
The quantum efficiency (η) of a photodiode can be calculated using the formula:
η = Responsivity * (h * c) / (q * λ)
where:
- h is Planck's constant (6.626 x 10^-34 J.s),
- c is the speed of light (3 x 10^8 m/s),
- q is the charge of an electron (1.6 x 10^-19 C), and
- λ is the wavelength.
Given that the responsivity is 0.294 A/W and the wavelength is 0.90 μm (or 0.90 x 10^-6 m), we can substitute these values into the formula:
η = 0.294 * (6.626 x 10^-34 * 3 x 10^8) / (1.6 x 10^-19 * 0.90 x 10^-6)
Solving this equation gives us the quantum efficiency.
Let's calculate:
η = 0.294 * (1.9878 x 10^-25) / (1.44 x 10^-25)
η = 0.405
So, the quantum efficiency of the photodiode is 0.405, which corresponds to option c.
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