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The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is:

Question

The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hours is:

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Solution

To calculate the amount of energy liberated in kilowatt hours, we can use Einstein's mass-energy equivalence equation, E = mc^2, where E is the energy, m is the mass defect, and c is the speed of light.

Step 1: Convert the mass defect from grams to kilograms. Since 1 kilogram is equal to 1000 grams, we divide the mass defect of 0.3 grams by 1000 to get 0.0003 kilograms.

Step 2: Calculate the energy using the mass-energy equivalence equation. E = (0.0003 kg) * (3 x 10^8 m/s)^2 E = 0.0003 kg * 9 x 10^16 m^2/s^2 E = 2.7 x 10^13 kg m^2/s^2

Step 3: Convert the energy from joules to kilowatt hours. Since 1 joule is equal to 2.77778 x 10^-7 kilowatt hours, we divide the energy of 2.7 x 10^13 kg m^2/s^2 by 2.77778 x 10^-7 to get the energy in kilowatt hours.

E (in kilowatt hours) = (2.7 x 10^13 kg m^2/s^2) / (2.77778 x 10^-7) E (in kilowatt hours) ≈ 9.72 x 10^19 kilowatt hours

Therefore, the amount of energy liberated in kilowatt hours is approximately 9.72 x 10^19 kilowatt hours.

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