The energy released per fission of a 92U235 nucleus is nearly200eV20eV200MeV2000eV

To address the question regarding the energy released per fission of a $^{235}_{92}\text{U}$ nucleus, we need to analyze the options provided:

1. Understanding Nuclear Fission: Nuclear fission is a process where the nucleus of an atom splits into two or more smaller nuclei along with the release of energy. The fission of $^{235}_{92}\text{U}$ is significant in both nuclear reactors and atomic bombs.

2. Energy Released: The typical energy released per fission event of a $^{235}_{92}\text{U}$ nucleus is approximately $200 \, \text{MeV}$. This value is well-established in nuclear physics literature.

3. Reviewing Options:

   • $20 \, \text{eV}$: This is extremely low for a fission event.
   • $200 \, \text{eV}$: Still too low for nuclear fission energy.
   • $200 \, \text{MeV}$: This is the correct value and reflects the energy released in fission.
   • $2000 \, \text{eV}$: Also too low for a fission event.

Based on the analysis of the above options, the correct answer would be:

Final Answer

The energy released per fission of a $^{235}_{92}\text{U}$ nucleus is nearly $200 \, \text{MeV}$.