273 cm3 de un gas ideal está a 0° C. Se calienta a presión constante hasta 10° C. Ahora ocupará:

1. Break Down the Problem

We have a gas at an initial volume and temperature that undergoes a change in temperature at constant pressure. We need to find the new volume of the gas after heating.

2. Relevant Concepts

The relevant concept here is Charles's Law, which states that at constant pressure, the volume of an ideal gas is directly proportional to its absolute temperature. Mathematically, this can be expressed as:

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$

Where:

• $V_1$ = initial volume
• $T_1$ = initial temperature in Kelvin
• $V_2$ = final volume
• $T_2$ = final temperature in Kelvin

3. Analysis and Detail

1. Convert the initial and final temperatures from Celsius to Kelvin:

   • $T_1 = 0° C = 273.15 \, K$
   • $T_2 = 10° C = 283.15 \, K$

2. Substitute the known values into the Charles's Law equation:

   • Initial volume, $V_1 = 273 \, cm^3$
   • Rearranging the equation to find $V_2$: $V_2 = V_1 \cdot \frac{T_2}{T_1}$

3. Plugging in the values: $V_2 = 273 \, cm^3 \cdot \frac{283.15 \, K}{273.15 \, K}$

4. Verify and Summarize

Now we will calculate $V_2$:

$V_2 = 273 \, cm^3 \cdot \frac{283.15}{273.15} \approx 273 \, cm^3 \cdot 1.0366 \approx 283.55 \, cm^3$

Final Answer

After heating the gas to 10° C, the new volume will occupy approximately 283.55 cm³.