Solve the equation for all real solutions in simplest form.d, squared, minus, 9, d, plus, 2, equals, 0d 2 −9d+2=0

Question

Solve the equation for all real solutions in simplest form.

Given the equation:
$d^2 - 9d + 2 = 0$
Find the values of $d$ that satisfy this equation.

🧐 Not the exact question you are looking for?Go ask a question

Solution

The equation you provided is a quadratic equation. The general form of a quadratic equation is ax^2 + bx + c = 0. In this case, a = 1, b = -9, and c = 2.

To solve for d, we can use the quadratic formula, which is d = [-b ± sqrt(b^2 - 4ac)] / (2a).

Substituting the values of a, b, and c into the formula, we get:

d = [9 ± sqrt((-9)^2 - 412)] / (2*1) d = [9 ± sqrt(81 - 8)] / 2 d = [9 ± sqrt(73)] / 2

So, the solutions for d are:

d = (9 + sqrt(73)) / 2 d = (9 - sqrt(73)) / 2

These are the real solutions for the equation in simplest form.

This problem has been solved

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.

Solve the equation for all real solutions in simplest form.d, squared, minus, 9, d, plus, 2, equals, 0d 2 −9d+2=0

Question