Solve the ODE :4 3 0y y y′′ ′− + =subject to the initial conditions y(0) = 1 andy'(0) = 2
Question
Solution 1
To solve the given ordinary differential equation (ODE), we will follow these steps:
Step 1: Write down the ODE in standard form: 4y''' - 3y'' + 0y' - y = 0
Step 2: Determine the characteristic equation by assuming a solution of the form y = e^(rt), where r is a constant: 4r^3 - 3r^2 + 0r - 1 = 0
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