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What is the heat change if 254 g of solid gold increases in temperature by 20 K to 1 d.p?(The molar heat capacity of solid gold is 25.42 J mol-1 K-1)

Question

What is the heat change if 254 g of solid gold increases in temperature by 20 K to 1 d.p?

(The molar heat capacity of solid gold is 25.42 J mol⁻¹ K⁻¹)

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Solution

To calculate the heat change, we can use the formula for heat change which is:

q = mcΔT

where: q = heat change m = mass c = specific heat capacity ΔT = change in temperature

However, we are given the molar heat capacity and the mass, so we first need to convert the mass of gold to moles. The molar mass of gold (Au) is approximately 197.0 g/mol.

So, the number of moles (n) = mass (m) / molar mass (M)

n = 254 g / 197.0 g/mol = 1.29 mol

Now we can calculate the heat change:

q = n * c * ΔT

q = 1.29 mol * 25.42 J mol-1 K-1 * 20 K = 654.3 J

So, the heat change is 654.3 J to 1 decimal place.

This problem has been solved

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