What is the specific heat capacity of a 250g object that needs 34.125kJ to have its temperature raised by 65.0 ∘ C?
Question
Solution 1
The specific heat capacity (c) of an object can be calculated using the formula:
c = Q / (m * ΔT)
where:
- Q is the heat energy absorbed or released (in joules),
- m is the mass of the object (in kilograms), and
- ΔT is the change in temperature (in degrees Celsius).
Given:
- Q = 34.125 kJ = 3412 Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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